Integrand size = 25, antiderivative size = 39 \[ \int x^{-1+n-p (1+q)} \left (a x^n+b x^p\right )^q \, dx=\frac {x^{-p (1+q)} \left (a x^n+b x^p\right )^{1+q}}{a (n-p) (1+q)} \]
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Time = 0.03 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.040, Rules used = {2039} \[ \int x^{-1+n-p (1+q)} \left (a x^n+b x^p\right )^q \, dx=\frac {x^{-p (q+1)} \left (a x^n+b x^p\right )^{q+1}}{a (q+1) (n-p)} \]
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Rule 2039
Rubi steps \begin{align*} \text {integral}& = \frac {x^{-p (1+q)} \left (a x^n+b x^p\right )^{1+q}}{a (n-p) (1+q)} \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.03 \[ \int x^{-1+n-p (1+q)} \left (a x^n+b x^p\right )^q \, dx=-\frac {x^{-p (1+q)} \left (a x^n+b x^p\right )^{1+q}}{a (-n+p) (1+q)} \]
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\[\int x^{-1+n -p \left (q +1\right )} \left (a \,x^{n}+b \,x^{p}\right )^{q}d x\]
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none
Time = 0.27 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.95 \[ \int x^{-1+n-p (1+q)} \left (a x^n+b x^p\right )^q \, dx=\frac {{\left (a x x^{-p q + n - p - 1} x^{n} + b x x^{-p q + n - p - 1} x^{p}\right )} {\left (a x^{n} + b x^{p}\right )}^{q}}{{\left (a n - a p + {\left (a n - a p\right )} q\right )} x^{n}} \]
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\[ \int x^{-1+n-p (1+q)} \left (a x^n+b x^p\right )^q \, dx=\int x^{n - p \left (q + 1\right ) - 1} \left (a x^{n} + b x^{p}\right )^{q}\, dx \]
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\[ \int x^{-1+n-p (1+q)} \left (a x^n+b x^p\right )^q \, dx=\int { {\left (a x^{n} + b x^{p}\right )}^{q} x^{-p {\left (q + 1\right )} + n - 1} \,d x } \]
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\[ \int x^{-1+n-p (1+q)} \left (a x^n+b x^p\right )^q \, dx=\int { {\left (a x^{n} + b x^{p}\right )}^{q} x^{-p {\left (q + 1\right )} + n - 1} \,d x } \]
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Timed out. \[ \int x^{-1+n-p (1+q)} \left (a x^n+b x^p\right )^q \, dx=\int x^{n-p\,\left (q+1\right )-1}\,{\left (a\,x^n+b\,x^p\right )}^q \,d x \]
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